[23909] in Kerberos
Re: Problems running kinit on HP-UX 11.00, 11i
daemon@ATHENA.MIT.EDU (Roland Dowdeswell)
Tue May 17 23:43:52 2005
To: Sam Hartman <hartmans@mit.edu>
In-reply-to: Your message of "Tue, 17 May 2005 16:51:06 EDT."
<tslmzqtr2yt.fsf@cz.mit.edu>
Date: Tue, 17 May 2005 17:04:11 -0400
From: Roland Dowdeswell <elric@imrryr.org>
Message-Id: <20050517210411.6DAE737042@arioch.imrryr.org>
cc: kerberos@mit.edu
Errors-To: kerberos-bounces@mit.edu
On 1116363066 seconds since the Beginning of the UNIX epoch
Sam Hartman wrote:
>
>>>>>> "Roland" == Roland Dowdeswell <elric@imrryr.org> writes:
>
> Roland> On 1116021302 seconds since the Beginning of the UNIX
> Roland> epoch
> Roland> Sam Hartman wrote:
> >>
>
> >> A design can be broken.
> >>
> >> I don't believe the implementation of pthread_once in the HP
> >> libc meets the API specification in POSIX. That counts as
> >> broken in my book.
>
> Roland> Looks like SunOS 5.7 provides a pthread_once() that
> Roland> returns true without calling anything if -lpthread is not
> Roland> specified. We probably need a more generic solution...
>
>Yep. Ken is looking into this.
This condition can be reasonably easily detected via:
static void set_has_pthread_once(void);
static inline int has_pthread_once_func(void);
int has_pthread_once = 0;
static void
set_has_pthread_once(void)
{
has_pthread_once = 1;
}
static inline int
has_pthread_once_func(void)
{
pthread_once_t once_control = PTHREAD_ONCE_INIT;
if (has_pthread_once)
return 1;
pthread_once(&once_control, set_has_pthread_once);
return has_pthread_once;
}
or some such. Although, it would probably make the code less full
of #ifdef's to simply implement krb5_pthread_once() which doesn't
use pthread_once() but simply manages its own mutex's.
--
Roland Dowdeswell http://www.Imrryr.ORG/~elric/
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