[10753] in cryptography@c2.net mail archive
Re: Lucky's 1024-bit post
daemon@ATHENA.MIT.EDU (Wei Dai)
Sun May 12 22:03:23 2002
Date: Tue, 30 Apr 2002 17:36:29 -0700
From: Wei Dai <weidai@eskimo.com>
To: cryptography@wasabisystems.com
Message-ID: <20020430173629.A18878@eskimo.com>
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In-Reply-To: <ca08c48076c1c61f0ddfbf6b899bd772@remailer.privacy.at>; from nobody@remailer.privacy.at on Wed, May 01, 2002 at 01:37:09AM +0200
On Wed, May 01, 2002 at 01:37:09AM +0200, Anonymous wrote:
> This is probably not the right way to approach the problem. Bernstein's
> relation-finding proposal to directly use ECM on each value, while
> asymptotically superior to conventional sieving, is unlikely to be
> cost-effective for 1024 bit keys. Better to extrapolate from the recent
> sieving results.
Yes, good point.
> For about $200 you can buy a 1000 MIPS CPU, and the memory needed for
> sieving is probably another couple of hundred dollars. So call it $500
> to get a computer that can sieve 1000 MIPS years in a year.
You need a lot more than a couple of hundred dollars for the memory,
because you'll need 125 GB per machine. See Robert Silverman's post at
http://groups.google.com/groups?hl=en&selm=8626nu%24e5g%241%40nnrp1.deja.com&prev=/groups%3Fq%3D1024%2Bsieve%2Bmemory%26start%3D20%26hl%3Den%26scoring%3Dd%26selm%3D8626nu%2524e5g%25241%2540nnrp1.deja.com%26rnum%3D21
According to pricewatch.com, 128MB costs $14, so each of your sieving
machines would cost about $14000 instead of $500.
> If we are willing to take one year to generate the relations then
> ($500 / 1000) x 8 x 10^10 is $40 billion dollars, used to buy
> approximately 80 million cpu+memory combinations.
($14000 / 1000) x 8 x 10^10 is $1.1 trillion. So my earlier estimate for a
$10 trillion 4-month machine was only off by a factor of 3, which is a
nice coincidence. :)
(Too bad about the memory, otherwise you can get your sieving machine
almost for free by writing a worm to take over half of the Internet, which
currently has about 190 million hosts.)
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