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Re: standardizing key schedules

daemon@ATHENA.MIT.EDU (Hal Finney)
Wed Feb 26 13:06:39 1997

Date: Wed, 26 Feb 1997 09:03:31 -0800
From: Hal Finney <hal@rain.org>
To: cryptography@c2.net, reinhold@world.std.com

From: "Arnold G. Reinhold" <reinhold@world.std.com>
> Since I started this, I should point out that with 256 byte random keys the
> resulting permutations are uniformly random as well. Each swap depends on a
> sum mod 256 one of whose terms is a random 8 bit quantity (a key byte) that
> differs for each swap. Since each of the S array values is swapped at least
> once, one can know nothing about their final values without the key.

If I understand what you're saying, this can't be true, since 256^256
is not a multiple of 256!.  So some permutations must be more likely
than others with 256 byte random keys.  However I think the bias would
be vanishingly small.

Consider a simplified case, with 3 terms.  The chart below shows a
hierarchy, first showing the three possibilities after the first word is
swapped randomly with each of the three choices, then at the second
level it shows the nine possible results after the second swap, and at
the third level it shows the 27 possible results after three swaps.

123		after 1 swap
 213		after 2 swaps
  312		after 3 swaps
  231		''
  213		''
 123		after 2 swaps
  321		after 3 swaps
  132		''
  123		''
 132		after 2 swaps
  231
  123		''
  132		''
213		after 1 swap
 123		after 2 swaps
  321		after 3 swaps
  132		''
  123		''
 213		after 2 swaps
  312		after 3 swaps
  231		''
  213		''
 231		after 2 swaps
  132		after 3 swaps
  213		''
  231		''
321		after 1 swap
 231		after 2 swaps
  132		after 3 swaps
  213		''
  231		''
 321		after 2 swaps
  123		after 3 swaps
  312		''
  321		''
 312		after 2 swaps
  213		after 3 swaps
  321		''
  312		''

For a final count of:

Perm	Count
-------------
123	4
132	5
213	5
231	5
312	4
321	4
---------
Total	27

Some of the permutations are slightly more likely than others.

Hal

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